I don't know why I'm having such a hard time wrapping my head around the thinking here. What I want to determine is: if you could buy something anywhere in the world, as long as you bought it on February 10th, how long would the planet have, in total? Ie, how long does February 10th last, starting at the International Dateline and then going all the way around?
Using
this as a baseline, New Years Day 2012, for example, starts at 5am on a Monday in Samoa. Then it happens everywhere else, obviously going all the way around the world and hitting American Samoa at 6am on a Tuesday. So is it 29 hours for that + 24 hours in a day? Is it that easy?
I could be missing something incredibly obvious here, or possibly I just lack basic math, but this is currently stumping me and my entire office. And google sucks for questions you don't know how to ask.
So, for example, right now it's February 7. The earliest time it was February 7 anywhere in the world was, in UTC, 10:00 AM on February 6; fourteen hours ahead of that is midnight, February 6/7. The latest time that it will be February 7 is, in UTC, noon on February 8; twelve hours ahead of that is midnight, Feburary 7/8.
The difference is two days and two hours, or 50 hours. (You'd expect 48 in theory, but the date line isn't straight.) I'm assuming here that the UTC+14 places don't have daylight savings time (they're near the equator, so it seems unlikely). You could also make an argument that nobody lives in UTC-12 and the westernmost inhabited timezone is UTC-11, which would knock off an hour.
posted by madcaptenor at 10:31 AM on February 7, 2012 [3 favorites]