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	  <title>Ask MetaFilter questions tagged with derivative</title>
      <link>http://ask.metafilter.com/tags/derivative</link>
      <description>Questions tagged with 'derivative' at Ask MetaFilter.</description>
	  <pubDate>Fri, 01 Aug 2008 19:23:47 -0800</pubDate> <lastBuildDate>Fri, 01 Aug 2008 19:23:47 -0800</lastBuildDate>

      <language>en-us</language>
	  <docs>http://blogs.law.harvard.edu/tech/rss</docs>
	  <ttl>60</ttl>	  
	<item>
	<title>A nowhere continuous derivative?</title>
	<link>http://ask.metafilter.com/98118/A%2Dnowhere%2Dcontinuous%2Dderivative</link>	
	<description>Is there a differentiable function f(x) such that the derivative is nowhere continuous?  That is, f&apos;(x) has no point of continuity? Googling has led me to believe this does not exist, though I can&apos;t find anything like a proof, only vague references to Baire classes.&lt;br&gt;
&lt;br&gt;
Can you tell me where I would find a proof?</description>
	<guid isPermaLink="false">tag:ask.metafilter.com,2008:site.98118</guid>
	<pubDate>Fri, 01 Aug 2008 19:23:47 -0800</pubDate>
	<category>analysis</category>
	<category>Baire</category>
	<category>continuous</category>
	<category>derivative</category>
	<category>discontinuous</category>
	<category>function</category>
	<dc:creator>thrako</dc:creator>
	</item>
	<item>
	<title>Copyright issues in creating an ebook?</title>
	<link>http://ask.metafilter.com/87304/Copyright%2Dissues%2Din%2Dcreating%2Dan%2Debook</link>	
	<description>I&apos;m thinking of creating an ebook that is a workbook companion for an existing popular investment book. What copyright issues do I have to consider? For example, can I title it &quot;The [&lt;em&gt;Investment Book Title&lt;/em&gt;] Workbook?&quot; Can I do it at all without getting permission first?</description>
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	<pubDate>Fri, 28 Mar 2008 14:27:17 -0800</pubDate>
	<category>copyright</category>
	<category>derivative</category>
	<category>ebook</category>
	<category>workbook</category>
	<dc:creator>SampleSize</dc:creator>
	</item>
	<item>
	<title>Copyright in screenshots?  Who owns it?</title>
	<link>http://ask.metafilter.com/55616/Copyright%2Din%2Dscreenshots%2DWho%2Downs%2Dit</link>	
	<description>Can anyone explain, in some detail, precisely *how* the taking and use of a screenshot of a program running on a computer can infringe the copyrights or trademarks of others? There&apos;s a foofaraw going on just now on one of the Wikipedia mailing lists about the fact that Wikimedia Commons has what I, personally, feel is *entirely* too strict a policy concerning screenshots (where, by too strict, I mean that in the example of a screenshot of a website in a browser, they&apos;re concerned with infringing on the copyright not only of the website and it&apos;s designers and copywriters -- which I could &lt;i&gt;just barely&lt;/i&gt; understand -- but also the trademark of the browser creator (for its logo) and the copyright of the creator of the desktop manager design -- Apple&apos;s Aqua, by example).&lt;br&gt;
&lt;br&gt;
My assertion is that if I create a screenshot, *I* own a copyright in it, and that any infringement could only be by defining it as a derivative work.  I thought I understood &quot;derivative work&quot;, but they&apos;re trying really hard to convince me I&apos;m out of my mind.&lt;br&gt;
&lt;br&gt;
To be clear, they don&apos;t require that the program be a browser: they&apos;re just as happy to claim these infringements about screenshots of other types of running programs.&lt;br&gt;
&lt;br&gt;
Certainly any of those party&apos;s lawers could convince them to sue, whether they have clear and reasonable grounds or not, and they have more money than you do -- though WMF certainly has a legal budget these days after a $1.5MUS pledge drive last month.&lt;br&gt;
&lt;br&gt;
So, in the real world, can a screenshot -- given that screenshots are almost uniformly made either for identification, illustration, or educational purposes -- *actually* infringe any of those things?&lt;br&gt;
&lt;br&gt;
(Extra points for case law; I&apos;ll be happy to look up the citations myself.)&lt;br&gt;
&lt;br&gt;
I know we have some lawyers, I know this won&apos;t be legal advice, I also know it&apos;s federal jurisdiction, so the usual &quot;I&apos;m in another state&quot; reply will matter less.  Any thoughts?</description>
	<guid isPermaLink="false">tag:ask.metafilter.com,2007:site.55616</guid>
	<pubDate>Tue, 23 Jan 2007 19:53:09 -0800</pubDate>
	<category>commons</category>
	<category>copyright</category>
	<category>derivative</category>
	<category>screenshot</category>
	<category>wikipedia</category>
	<dc:creator>baylink</dc:creator>
	</item>
	<item>
	<title>Dumb calculus question...</title>
	<link>http://ask.metafilter.com/42526/Dumb%2Dcalculus%2Dquestion</link>	
	<description>Stupid calculus question inside. So I have a detailed plot of a curve that looks rather like exponential decay, but no equation has been given to me to describe the curve.&lt;br&gt;
&lt;br&gt;
I would like to find the instantaneous slope of the curve at any given point along its length. Am I correct in assuming that this is really just the first derivative? (I took calculus a long time ago). &lt;br&gt;
&lt;br&gt;
I have been provided with a method for finding slope at any point along the curve by physically drawing a tangent to the point and computing ITS slope. Given my desire to use basic calculus to solve this instead, is there an easier/better way for me to calculate slope that doesn&apos;t involve irritating sketching of tangent lines and use of straight edges?&lt;br&gt;
&lt;br&gt;
A concise, simple-to-grok explanation of what I need to do will win the day....</description>
	<guid isPermaLink="false">tag:ask.metafilter.com,2006:site.42526</guid>
	<pubDate>Wed, 19 Jul 2006 15:27:50 -0800</pubDate>
	<category>basic</category>
	<category>calculus</category>
	<category>derivative</category>
	<category>derivatives</category>
	<category>math</category>
	<category>mathematics</category>
	<category>stupid</category>
	<category>stupidity</category>
	<dc:creator>killdevil</dc:creator>
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