Comments on: How to get a RSS feed working without direct access to the site

Question: How to get a RSS feed working without direct access to the site

razorfrog — Mon, 28 Jul 2008 11:28:06 -0800

How can I make an RSS feed from someone else's content?

A strange situation has come up where I need to take a "daily feature" page, with content that changes daily, and make an RSS feed out of it. The problem is, I don't have direct access to the site, as I've been tasked with a small side project (creating an auto-mailing list), and the main design team is busy working elsewhere. Is there a way to create a feed without access to the site - some kind of outside service?

One other option - there is some sort of RSS feed already serving this content, but it's PHP based, and coming up as invalid anywhere I try to convert it to XML. But if that could be converted to proper XML, that would also solve my problem.

Very strange, I know, but I appreciate any help.

The content page
The quazi-RSS feed

By: junesix

junesix — Mon, 28 Jul 2008 12:11:55 -0800

The feed seems fine to me or at least Google Reader had no problems subscribing to it. RSS is just an XML format so I'm not sure what you're trying to convert it to.

By: mkb

mkb — Mon, 28 Jul 2008 12:22:42 -0800

That PHP RSS generator is setting the wrong Content-type header. It SHOULD be text/xml

By: XMLicious

XMLicious — Mon, 28 Jul 2008 12:38:14 -0800

junesix, how many items do you see through Google Reader? In the source code there appear to be five items, but FF3 only displays one item and IE7 throws an error.

The person who wrote the .php made a whole bunch of mistakes that I can see - they didn't XML-encode ampersands in the URLs within the and tags, those CDATA sections will cause problems, and as you observe razorfrog the RSS structure is all messed up.

There isn't any way to automatically fix this. If you don't have access to change that .php page you would have to write code in whatever language you're familiar with to read in the output of that page, fix the mistakes in it, and redisplay it.

By: XMLicious

XMLicious — Mon, 28 Jul 2008 12:39:52 -0800

Heh heh, that was ironic - that should be "...they didn't XML-encode ampersands in the URLs within the <link /> and <guid /> tags,"

By: kepano

kepano — Mon, 28 Jul 2008 12:54:41 -0800

I'm not sure this is what you're looking for but Ponyfish is able to generate RSS feeds from external sources.

By: gemmy

gemmy — Mon, 28 Jul 2008 13:18:51 -0800

I have used feed43.com for this purpose before. It works really well for me, over probably 20 different sites.

By: aubilenon

aubilenon — Mon, 28 Jul 2008 14:03:51 -0800

The excellently named RSSPECT seems to do this.

By: chrisbucks

chrisbucks — Mon, 28 Jul 2008 18:03:23 -0800

I've used Dapper for this kind of thing, but as others have already said... lots of other sources to do this with more complexity. Dapper is fairly simplistic but easy to use.