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      <title>Comments on: Help me find the right angle!</title>
      <link>http://ask.metafilter.com/75862/Help-me-find-the-right-angle/</link>
      <description>Comments on Ask MetaFilter post Help me find the right angle!</description>
	  	  <pubDate>Fri, 09 Nov 2007 10:49:25 -0800</pubDate>
      <lastBuildDate>Fri, 09 Nov 2007 10:49:25 -0800</lastBuildDate>
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<item>
  	<title>Question: Help me find the right angle!</title>
  	<link>http://ask.metafilter.com/75862/Help-me-find-the-right-angle</link>	
  	<description>I&apos;m looking for an online resource that will allow me to enter a time (in hours, minutes, seconds) and return a listing of the angles between the hands if that time was displayed on an analog clock. Can anyone point me in the right direction?</description>
  	<guid isPermaLink="false">post:ask.metafilter.com,2008:site.75862</guid>
  	<pubDate>Fri, 09 Nov 2007 10:42:36 -0800</pubDate>
  	<dc:creator>langeNU</dc:creator>
	
	<category>analog</category>
	
	<category>clock</category>
	
	<category>angles</category>
	
	<category>time</category>
	
</item>
<item>
  	<title>By: BSummers</title>
  	<link>http://ask.metafilter.com/75862/Help-me-find-the-right-angle#1127198</link>	
  	<description>paste this in your URL bar&lt;br&gt;
&lt;br&gt;
javascript:$h = prompt(&amp;quot;Hour&amp;quot;,&amp;quot;&amp;quot;); $m = prompt(&amp;quot;Minute&amp;quot;,&amp;quot;&amp;quot;); $ha = $h*30; $hm = $m*6; alert($hm - $ha + &apos; degrees&apos;);</description>
  	<guid isPermaLink="false">comment:ask.metafilter.com,2008:site.75862-1127198</guid>
  	<pubDate>Fri, 09 Nov 2007 10:49:25 -0800</pubDate>
  	<dc:creator>BSummers</dc:creator>
</item>
<item>
  	<title>By: mumkin</title>
  	<link>http://ask.metafilter.com/75862/Help-me-find-the-right-angle#1127204</link>	
  	<description>So for 10:46:33, for example, you&apos;re wanting the angles formed by hour &amp;amp; minute hands, hour and second hands, and minute and second hands? Do you want it to reflect the reality of an analog clock, such that at 4:30:00 the hour hand is halfway between 4 and 5?&lt;br&gt;
&lt;br&gt;
(not that I know of a slew of resources and am asking to differentiate between them... just wondering for purposes of clarification)</description>
  	<guid isPermaLink="false">comment:ask.metafilter.com,2008:site.75862-1127204</guid>
  	<pubDate>Fri, 09 Nov 2007 10:52:52 -0800</pubDate>
  	<dc:creator>mumkin</dc:creator>
</item>
<item>
  	<title>By: vacapinta</title>
  	<link>http://ask.metafilter.com/75862/Help-me-find-the-right-angle#1127206</link>	
  	<description>This is an arithmetic problem. The angle of the hour hand, however, needs to include a correction for how many minutes between the hour marks: $h*30+$m*0.5</description>
  	<guid isPermaLink="false">comment:ask.metafilter.com,2008:site.75862-1127206</guid>
  	<pubDate>Fri, 09 Nov 2007 10:54:57 -0800</pubDate>
  	<dc:creator>vacapinta</dc:creator>
</item>
<item>
  	<title>By: BSummers</title>
  	<link>http://ask.metafilter.com/75862/Help-me-find-the-right-angle#1127213</link>	
  	<description>with vacapintas update - ty!&lt;br&gt;
&lt;br&gt;
javascript:$h = prompt(&amp;quot;Hour&amp;quot;,&amp;quot;&amp;quot;); $m = prompt(&amp;quot;Minute&amp;quot;,&amp;quot;&amp;quot;); $ha = $h*30+$m*0.5; $hm = $m*6; alert($hm - $ha + &apos; degrees&apos;);</description>
  	<guid isPermaLink="false">comment:ask.metafilter.com,2008:site.75862-1127213</guid>
  	<pubDate>Fri, 09 Nov 2007 10:57:37 -0800</pubDate>
  	<dc:creator>BSummers</dc:creator>
</item>
<item>
  	<title>By: langeNU</title>
  	<link>http://ask.metafilter.com/75862/Help-me-find-the-right-angle#1127224</link>	
  	<description>To attempt to clarify some, assume the hour hand &apos;jumps&apos; 0.5 degrees every minute on the minute (1/60th of the total 30 degree movement in an hour). Lets also have the minute hand move on the minute as well, so the minute hand would jump 6 degrees (1/60th of the total 360 degree movement in the hour). The second hand would jump 6 degrees every second.&lt;br&gt;
&lt;br&gt;
Thus, at 12:00:00 there will be 0 degrees between the hour and the minute and the second hand, and at 12:01:00 there would be 5.5 degrees between the hour and the minute hand, 0.5 degrees between the second hand and the hour hand, and 6 degrees between the second and the minute hand.&lt;br&gt;
&lt;br&gt;
Also, for clarity, lets have angles be calculated as positive when moving in a clockwise direction from any given &apos;reference&apos; hand.</description>
  	<guid isPermaLink="false">comment:ask.metafilter.com,2008:site.75862-1127224</guid>
  	<pubDate>Fri, 09 Nov 2007 11:04:44 -0800</pubDate>
  	<dc:creator>langeNU</dc:creator>
</item>
<item>
  	<title>By: DevilsAdvocate</title>
  	<link>http://ask.metafilter.com/75862/Help-me-find-the-right-angle#1127225</link>	
  	<description>BSummer&apos;s (on preview: his first) solution assumes that the hour hand points directly at its number for the entire hour; i.e., between 1:00:00 p.m. and 1:59:59 p.m. the hour hand is pointing directly at the &amp;quot;1,&amp;quot; and at 2:00:00 p.m. it moves to point to the &amp;quot;2.&amp;quot;  That&apos;s not how most analog clocks work.  Also, his formula (on preview: both) results in angles between -360 and +360 degrees.  I&apos;m assuming you want a more commonsense definition of angle, which would be 0-180 degrees.&lt;br&gt;
&lt;br&gt;
It should be easy enough to set something like this up in Excel:&lt;br&gt;
&lt;br&gt;
Enter hours in A1, minutes in A2, seconds in A3.&lt;br&gt;
&lt;br&gt;
Intermediate calculations: these represent the number of degrees, clockwise from 12, you must go to get to each hand:&lt;br&gt;
&lt;br&gt;
In B1, enter =MOD((A1+A2/60+A3/3600)*30,360)&lt;br&gt;
In B2, enter =(A2+A3/60)*6&lt;br&gt;
In B3, enter =A3*6&lt;br&gt;
&lt;br&gt;
Angle between the hour and minute hands:&lt;br&gt;
=ABS(MOD(B1-B2+180,360)-180)&lt;br&gt;
&lt;br&gt;
Angle between the hour and second hands:&lt;br&gt;
=ABS(MOD(B1-B3+180,360)-180)&lt;br&gt;
&lt;br&gt;
Angle between the minute and second hands:&lt;br&gt;
=ABS(MOD(B2-B3+180,360)-180)</description>
  	<guid isPermaLink="false">comment:ask.metafilter.com,2008:site.75862-1127225</guid>
  	<pubDate>Fri, 09 Nov 2007 11:05:16 -0800</pubDate>
  	<dc:creator>DevilsAdvocate</dc:creator>
</item>
<item>
  	<title>By: DevilsAdvocate</title>
  	<link>http://ask.metafilter.com/75862/Help-me-find-the-right-angle#1127229</link>	
  	<description>On further preview: my solution assumes continuous motion of all hands, not the &amp;quot;jumps&amp;quot; specified by langeNU&apos;s most recent comment.</description>
  	<guid isPermaLink="false">comment:ask.metafilter.com,2008:site.75862-1127229</guid>
  	<pubDate>Fri, 09 Nov 2007 11:06:11 -0800</pubDate>
  	<dc:creator>DevilsAdvocate</dc:creator>
</item>
<item>
  	<title>By: DevilsAdvocate</title>
  	<link>http://ask.metafilter.com/75862/Help-me-find-the-right-angle#1127230</link>	
  	<description>&lt;i&gt;Also, for clarity, lets have angles be calculated as positive when moving in a clockwise direction from any given &apos;reference&apos; hand.&lt;/i&gt;&lt;br&gt;
&lt;br&gt;
So, in your example of 12:01:00, does that mean that the hour-&amp;gt;minute angle should give a different result than the minute-&amp;gt;hour angle?  If so, should the latter return -5.5 degrees, or should it return 354.5 degrees?</description>
  	<guid isPermaLink="false">comment:ask.metafilter.com,2008:site.75862-1127230</guid>
  	<pubDate>Fri, 09 Nov 2007 11:09:07 -0800</pubDate>
  	<dc:creator>DevilsAdvocate</dc:creator>
</item>
<item>
  	<title>By: langeNU</title>
  	<link>http://ask.metafilter.com/75862/Help-me-find-the-right-angle#1127232</link>	
  	<description>Continuous motion is fine as well!</description>
  	<guid isPermaLink="false">comment:ask.metafilter.com,2008:site.75862-1127232</guid>
  	<pubDate>Fri, 09 Nov 2007 11:11:14 -0800</pubDate>
  	<dc:creator>langeNU</dc:creator>
</item>
<item>
  	<title>By: langeNU</title>
  	<link>http://ask.metafilter.com/75862/Help-me-find-the-right-angle#1127236</link>	
  	<description>And after forgetting to preview, it doesn&apos;t really matter which way the angle is presented, I was just trying to give a reference point so people didn&apos;t have to get confused with negative angles.</description>
  	<guid isPermaLink="false">comment:ask.metafilter.com,2008:site.75862-1127236</guid>
  	<pubDate>Fri, 09 Nov 2007 11:12:39 -0800</pubDate>
  	<dc:creator>langeNU</dc:creator>
</item>
<item>
  	<title>By: demiurge</title>
  	<link>http://ask.metafilter.com/75862/Help-me-find-the-right-angle#1127372</link>	
  	<description>The solution DevilsAdvocate gave looks good.  It would be fairly trivial to make this into some sort of online form-based application if you really needed such a thing.&lt;br&gt;
&lt;br&gt;
I was interested in this problem and made a simple chart showing the relationship between the hours and minutes and the angle between the hand.  You can view it &lt;a href=&quot;http://www.polyatomic.org/clock_angle.png&quot;&gt;here&lt;/a&gt;. The x axis is the hour; y axis is minutes.</description>
  	<guid isPermaLink="false">comment:ask.metafilter.com,2008:site.75862-1127372</guid>
  	<pubDate>Fri, 09 Nov 2007 12:39:27 -0800</pubDate>
  	<dc:creator>demiurge</dc:creator>
</item>
<item>
  	<title>By: langeNU</title>
  	<link>http://ask.metafilter.com/75862/Help-me-find-the-right-angle#1127418</link>	
  	<description>Don&apos;t really need it to be online, I just figured that it might exist out there already. &lt;br&gt;
&lt;br&gt;
I thought I remembered seeing a Java applets where you could drag the hands on the face of a clock at some point in the past.</description>
  	<guid isPermaLink="false">comment:ask.metafilter.com,2008:site.75862-1127418</guid>
  	<pubDate>Fri, 09 Nov 2007 13:01:57 -0800</pubDate>
  	<dc:creator>langeNU</dc:creator>
</item>

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