Question: Use a regular expression to parse a directory tree

toomuch — Tue, 11 Apr 2006 11:25:49 -0800

I'm trying to write a regex that gets passed into a java class to validate that a file is in a certain directory structure.

Okay folks here's the deal. I have a closed source java class with a method that will tell me if a particular web resource is in one of it's predefined directory structures. The directory structures are defined as regular expressions in an XML file like this:

/var/www/.*
/home/user1/www/.*

I pass in the real path to a published jsp or some other file like this one:

/home/user1/www/test.jsp

and this method should return true if the file is in one of it's configured directory structures.

I'm trying to write a regular expression that will match all files/directories in the /home file tree except for a single user. Something like:

/home/.*
/home/^user2

but i want it in a single regular expression. That way if i pass in /home/user1/test.jsp I get a true but if I pass in /home/user2/test.jsp I get a false. I've been toying with something like "/home/[.*&&[^(user2/.*)]]" but it doesn't work. Hopefully that makes sense. Anyone, anyone?

By: kenko

kenko — Tue, 11 Apr 2006 11:38:24 -0800

Can't test this thoroughly now but try:
/home(?!/user2)/.*

By: kenko

kenko — Tue, 11 Apr 2006 11:40:23 -0800

/home/(?!user2).* is a more straightforward version of that.

By: toomuch

toomuch — Tue, 11 Apr 2006 11:42:13 -0800

Duh a lookahead. I can't believe it was that simple. Thanks kenko, you're a genius.

Comments on: Use a regular expression to parse a directory tree

Question: Use a regular expression to parse a directory tree

By: kenko

By: kenko

By: toomuch