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Comments on Ask MetaFilter post Algebra QuestionSat, 17 Nov 2012 11:35:42 -0800Sat, 17 Nov 2012 11:38:08 -0800en-ushttp://blogs.law.harvard.edu/tech/rss60Question: Algebra Question
http://ask.metafilter.com/229095/Algebra-Question
Can anyone help with an algebra question I am trying to help my neice with her homework. <br /><br /> (9/2m) - (m+4)/4m = 5/36<br>
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11th grade algebra- do you multiply entire equation by 2m? lowest common denominator? help. An explanation would be great and also any websites that help with algebra would be great too. Thanks.post:ask.metafilter.com,2012:site.229095Sat, 17 Nov 2012 11:35:42 -0800Summer FallmathalgebraBy: coolsara
http://ask.metafilter.com/229095/Algebra-Question#3315608
I recently discovered this site:<a href="http://www.khanacademy.org/math/algebra/solving-linear-equations-and-inequalities"> Kahn Academy</a>. The way that equation is written out, I can't really help you.comment:ask.metafilter.com,2012:site.229095-3315608Sat, 17 Nov 2012 11:38:08 -0800coolsaraBy: Green With You
http://ask.metafilter.com/229095/Algebra-Question#3315613
Multiply the whole equation by 4m, that gets rid of the m's in the denominator. Then multiply the whole equation by 36 to get rid of the all remaining denominators. At this point you can simplify the equation to a point where solving it should be easy.comment:ask.metafilter.com,2012:site.229095-3315613Sat, 17 Nov 2012 11:42:18 -0800Green With YouBy: peacheater
http://ask.metafilter.com/229095/Algebra-Question#3315614
Here we go: <br>
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Multiply the top and bottom of the first term on the left hand side by 2 to get: <br>
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18/4m -(m+4)/4m = 5/36<br>
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So now both term on the left hand side have 4m as the denominator so we can write it as: <br>
<br>
(18-(m+4))/4m = 5/36<br>
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Expanding the bracket in the numerator on the left hand side we get: <br>
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(18-m-4)/4m = 5/36<br>
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(14-m)/4m=5/36<br>
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Multiply both sides by 4 (to get rid of the 4 and make the denominator on the right hand side more tractable) and we get: <br>
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(14-m)/m = (5*4)/36<br>
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Now 36 = 9*4<br>
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Therefore we can cancel out the 4 in the numerator on the right hand side and change 36 to 9 giving us: <br>
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(14-m)/m = 5/9<br>
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Now cross-multiply the two sides: <br>
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9*(14-m) = 5m<br>
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Expanding: <br>
126-9m = 5m <br>
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Take the 9m term to the other side: <br>
126 = 14m <br>
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Now remember that 126 = 9*14 <br>
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So m = 126/14 = 9.comment:ask.metafilter.com,2012:site.229095-3315614Sat, 17 Nov 2012 11:43:20 -0800peacheaterBy: idb
http://ask.metafilter.com/229095/Algebra-Question#3315627
FYI you can <a href="http://www.wolframalpha.com/input/?i=%289%2F2m%29+-+%28m%2B4%29%2F4m+%3D+5%2F36">enter algebra into wolfram-alpha</a> and get a step-by-step solution.comment:ask.metafilter.com,2012:site.229095-3315627Sat, 17 Nov 2012 12:05:37 -0800idbBy: deathpanels
http://ask.metafilter.com/229095/Algebra-Question#3315651
(9/2m) - (m+4)/4m = 5/36<br>
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It would sure be great if we didn't have that (1/4m) in there because it's hard to work with. So let's multiple both side of the equation by 4m.<br>
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4m((9/2m) - (m+4)/4m) = 4m(5/36)<br>
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Which reduces to<br>
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18 - m + 4 = (5/9)m<br>
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Add m to both sides to get<br>
<br>
18 - 4 = (5/9)m + m<br>
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Or<br>
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14 = (14/9)m<br>
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Multiply both sides of the equation by (9/14)<br>
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9 = mcomment:ask.metafilter.com,2012:site.229095-3315651Sat, 17 Nov 2012 12:36:20 -0800deathpanelsBy: Obscure Reference
http://ask.metafilter.com/229095/Algebra-Question#3315712
When I teach this, I have them multiply by the LCD which is 36m.<br>
You get:<br>
<br>
162 - 9(m + 4) = 5m<br>
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162 - 36 = 9m + 5m<br>
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126 = 14m<br>
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so m = 9comment:ask.metafilter.com,2012:site.229095-3315712Sat, 17 Nov 2012 13:50:15 -0800Obscure ReferenceBy: one4themoment
http://ask.metafilter.com/229095/Algebra-Question#3315885
I actually went with multiplying the first term by 2 (so not changing the number, just how it's represented), which yields 18/4m - (m+4)/4m = 5/36... so 4m = 36... so m = 9... (and also 18-(m+4)=5... so m=9...) which is just a test to make sure the first value is correct.<br>
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It's been years since I took algebra so I started off with 1/2 - 1/4 = x (to refresh my memory of the rules of fraction subtraction)... 1/2 is the same as 2/4... so I rewrote as 2/4 - 1/4 = x... and so x is 1/4... realizing that the bottom remains consistent I was able to realize that once you change 9/2m to 18/4m you've got two equations that you can use to test the value...<br>
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Perhaps not the *best* way to solve, but just a demonstration that using what you know to figure out what you don't know works, sometimes.comment:ask.metafilter.com,2012:site.229095-3315885Sat, 17 Nov 2012 18:22:08 -0800one4themomentBy: one4themoment
http://ask.metafilter.com/229095/Algebra-Question#3315886
Also I loved this question, and I spent a few minutes destroying a piece of scrap paper with my scribbles :)comment:ask.metafilter.com,2012:site.229095-3315886Sat, 17 Nov 2012 18:23:43 -0800one4themomentBy: Summer Fall
http://ask.metafilter.com/229095/Algebra-Question#3316604
Thank you all!comment:ask.metafilter.com,2012:site.229095-3316604Sun, 18 Nov 2012 18:44:30 -0800Summer Fall