January 5, 2012 12:25 PM Subscribe
This is pretty straightforward algebra/chemistry which is why I'm embarrassed to ask my co-workers to help me so...
posted by Katine to Science & Nature (8 answers total) 4 users marked this as a favorite
If I have the dilution ranges of a series of solutions of MSG, how can I figure out, in grams, how much MSG I need in 1L of water to make the stock solution? I get that:
x M =y moles/z L
Let's say my stock would be 1.0x10(-1)M. And the molar mass of MSG is 169.111g/mol.
Given the above:
0.1M (msg) = 0.1moles/1.0 liter
and converting moles to grams = 0.1 moles x 169.111g/mol = 16.9g of MSG/L
Is that it? Or did I miss some element? It seems too simple but it's been a while.