Amperes to Arms current draw conversion confusion.
September 6, 2011 9:02 AM Subscribe
In measurements of electrical current draw, how do "amperes" compare to "Arms"?
I'm spec'ing mains power to an amplifier right now and its spec sheet reads:
Peak inrush current draw: 5 A
but then for operation current draw at switches to the measurement unit of "Arms", eg -
Quiescent Power (no load): 2.8 Arms
1/3 of full power (-5dB): 18 Arms
My google-fu is failing me and I can't seem to figure out any calculations relating "amps" and "arms" together.
If you want the specific example, here's the link to the PDF:
http://labgruppen.com/media/downloads/product/fP2400Q_ETL_spec.pdf
I'm spec'ing mains power to an amplifier right now and its spec sheet reads:
Peak inrush current draw: 5 A
but then for operation current draw at switches to the measurement unit of "Arms", eg -
Quiescent Power (no load): 2.8 Arms
1/3 of full power (-5dB): 18 Arms
My google-fu is failing me and I can't seem to figure out any calculations relating "amps" and "arms" together.
If you want the specific example, here's the link to the PDF:
http://labgruppen.com/media/downloads/product/fP2400Q_ETL_spec.pdf
flug has it, and although IANAEE I think you can just treat the rms value as the current draw of the device and be fine (that's why they give you the rms value).
I'm sure a friendly mefite will correct me if I'm wrong!
posted by samj at 9:23 AM on September 6, 2011
I'm sure a friendly mefite will correct me if I'm wrong!
posted by samj at 9:23 AM on September 6, 2011
Response by poster: *facepalm*
seeing it with the subscript makes so much more sense.
Thanks all.
posted by aloiv2 at 9:24 AM on September 6, 2011
seeing it with the subscript makes so much more sense.
Thanks all.
posted by aloiv2 at 9:24 AM on September 6, 2011
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This is a way of measuring average amps over a period of time. See for example, wiki.
posted by flug at 9:09 AM on September 6, 2011