How do I run 20ish LEDs with a LED Driver built to run 1 large LED ?
June 20, 2011 8:49 PM Subscribe
I want to drive 20ish LEDs, should I run them as series or parallel and why ?
I am looking to make a bike light for a friend with a "
Bucktoot" LED driver left over from another project . the questions are; would there be any reason(s) I can't run 350 mA worth of LEDs with this driver ?
Also ,would I want to run the LEDs in a series or in parallel and why ?
posted by 70klicks to sports, hobbies, & recreation (8 answers total) 3 users marked this as a favorite
Whether you want to do them in series or parallel would depend on what kind of LEDs you have. It'll be best if all of your LEDs are identical. The principle is that by putting LEDs in parallel, the current is divided up among them, while by putting them in series, they all get the same current, but the voltage requirement adds up. According to sparkfun, you need to give the converter at least 2 volts more than the LEDs need, and no more than 28 volts or less than 5.
So here's some examples:
If you have 20 average LEDs, which might want about 17 mA each, put them all in parallel so the total current adds up to about 350, which is what the driver wants to supply.
If you have 6 high-current LEDs which want about 350 mA each, put them in series so the 350 mA goes through them all. That's the example in the datasheet. You probably couldn't have more than about 6-8 LEDs in series, because the total voltage drop will add up. If each LED drops 3V, then 8 of them add up to 24V, which is about the most that the driver can supply. And you'd need to put in 26V to make sure it has the 2 volts headroom it wants.
If you have a bunch of 50 mA, 2V LEDs, you could have 7 in parallel, so the current adds up to 350, and run the converter off 5V or four 1.5V batteries, since the converter needs 2 volts more than the LED voltage drop. You could also make 7 strings of 3 LEDs each, as long as you can give the converter about 8 or 9 volts to work with.
posted by moonmilk at 10:06 PM on June 20, 2011 [1 favorite]