How should I rank these alternative poker hands?
May 13, 2011 12:26 PM Subscribe
I'm trying to rank some non-proper poker hands within the conventional poker hand-ranking framework. I would like to rank them conventionally, i.e. on their probability of occurring in a straight, five-card deal.
The non-proper hands are:
(1) "Four-card straight" (four cards in a row);
(2) "Four-card flush" (four cards of the same suit);
(3) "Four-card straight flush" (four cards in a row of the same suit);
(4) "Same-color flush" (all 5 red cards or all 5 black cards);
(5) "Straight same-color flush" (a straight composed of all black cards or all red cards);
(6) "Four-card straight same-color flush" (a four-card straight composed of all black cards or all red cards).
My probability skills are "OK" (the odds for the four-card flush and same-color flush are straightforward), but some of them (particularly the straights) seem too tricky for me.
posted by mrgrimm to Sports, Hobbies, & Recreation (9 answers total) 2 users marked this as a favorite
Here's how I posit the rankings, from low to high:
* High card
* 1 pair
* Same-color flush (4)
* Four-card flush (2)
* Four-card straight (1)
* 2 pair
* Four-card straight same-color flush (6)
* Four-card straight flush (3)
* 3 of a kind
* Straight same-color flush (5)
* Full House
* 4 of a kind
* Straight Flush
* 5 of a kind (if wild cards available)
More specific questions: 1) is it harder to get a Four-card straight than a Four-card flush? (I think so, but not sure); 2) Is 3 of a kind harder to get than a Four-card straight flush?; 3) Is a Full House harder to get than a Straight same-color flush?
But my general question is: Based on probability in a straight 5-card deal, where should those 6 non-proper hands rank within the conventional poker hand structure?
Can you tell it's Friday? ^_^