A = W*L;
L = W+2.3;
A = W*(W+2.3);
5.7 = W*(W+2.3)
Does this make sense to you? Can you take it from there? Also, is this homework? posted by telegraph at 5:01 PM on April 13, 2009 [1 favorite]
Great, thanks so much, posted by Benzle at 5:03 PM on April 13, 2009
Area of triangle= (Length*Width)/2
(2.3x*x)/2=5.7
x=2.2263
So width=2.2263 and length=5.1205 posted by Chan at 5:04 PM on April 13, 2009
L x W = 5.7
L = W + 2.3
W(W + 2.3) = 5.7
W^2 + 2.3W = 5.7
W^2 + 2.3W - 5.7 = 0
W = 1.5
L = 1.5 + 2.3 = 3.8 posted by bowmaniac at 5:04 PM on April 13, 2009
bowmaniac,
how do you get from step,
W^2 + 2.3W - 5.7 = 0
to,
W = 1.5
When I try this in the quadratic formula I get a negative sqr. root
I.E.
(-2.3 +- sqrrt.(2.3^2 -4(-5.7))/2 posted by Benzle at 5:08 PM on April 13, 2009
You've got a positive square root there, you're just missing the double negative:
(2.32- 4 (-5.7))/2) posted by Lemurrhea at 5:12 PM on April 13, 2009
I cheated and used http://www.math.com/students/calculators/source/quadratic.htm
a = 1
b = 2.3
c = -5.7 posted by bowmaniac at 5:13 PM on April 13, 2009
Benzle -- note that the "+-" in the quadratic formula is an either/or -- there are two solutions, one using plus and the other using minus. At least one of these is positive in this situation. posted by telegraph at 5:14 PM on April 13, 2009
OK, based on your previous "Help-me-open-a-curry-restaurant-franchise-Filter" question, I'm going to assume this is not your homework. So:
Let the length and width be "L" and "W". Then:
L = W + 2.3
The area of a rectangle is the product of its length and width, so:
L * W = 5.7
that assumes that the area is 5.7 square feet; you didn't specify the unit of the area, and the question is unanswerable without it. anyway...
L = W+2.3;
A = W*(W+2.3);
5.7 = W*(W+2.3)
Does this make sense to you? Can you take it from there? Also, is this homework?
posted by telegraph at 5:01 PM on April 13, 2009 [1 favorite]